X^2+y^2=180X-y=-6

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Solution for X^2+y^2=180X-y=-6 equation:



X^2+X^2=180X-X=-6
We move all terms to the left:
X^2+X^2-(180X-X)=0
We add all the numbers together, and all the variables
X^2+X^2-(+179X)=0
We add all the numbers together, and all the variables
2X^2-(+179X)=0
We get rid of parentheses
2X^2-179X=0
a = 2; b = -179; c = 0;
Δ = b2-4ac
Δ = -1792-4·2·0
Δ = 32041
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{32041}=179$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-179)-179}{2*2}=\frac{0}{4} =0 $
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-179)+179}{2*2}=\frac{358}{4} =89+1/2 $

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